How to get a Random Item in a Set in C# - Step by Step Examples

How to get a Random Item in a Set in C# ?

Answer

To get a random item from a set in C#, you can utilize the `Random` class along with the `ElementAt` LINQ extension method.

✐ Examples

1 Get Random Item from Set

In this example,

We import necessary namespaces including `System.Linq` and `System.Collections.Generic`.
We create a set, for example, a HashSet named `mySet`, and add elements to it.
We initialize a `Random` object to generate random numbers.
We use LINQ's `ElementAt` method along with `Random.Next` to retrieve a random item from the set.
Finally, we print the random item to the console.

C# Program

using System;
using System.Linq;
using System.Collections.Generic;

class Program
{
    static void Main(string[] args)
    {
        // Create and populate the set
        HashSet<int> mySet = new HashSet<int>() { 1, 2, 3, 4, 5 };

        // Initialize random number generator
        Random random = new Random();

        // Get random item from set
        int randomItem = mySet.ElementAt(random.Next(mySet.Count));

        // Print random item
        Console.WriteLine("Random item from set: " + randomItem);
    }
}

Output

Random item from set: [random value]

Summary

In this tutorial, we learned How to get a Random Item in a Set in C# language with well detailed examples.

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