How to Filter Elements of an Array based on a Condition in Rust - Step by Step Examples

How to Filter Elements of an Array based on a Condition in Rust ?

Answer

To filter elements of an array based on a condition in Rust, you can use iterators along with filter and collect methods.

✐ Examples

1 Filter Even Numbers

In this example,

We have a vector named numbers containing integers.
We use iterators along with filter method to filter out even numbers into a new vector named even_numbers.
We print the filtered vector to demonstrate the filtering.

Rust Program

fn main() {
    let numbers = vec![1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
    let even_numbers: Vec<_> = numbers.into_iter().filter(|&n| n % 2 == 0).collect();
    println!("Even Numbers: {:?}", even_numbers);
}

Output

Even Numbers: [2, 4, 6, 8, 10]

2 Filter Strings by Length

In this example,

We have a vector named words containing strings.
We use iterators along with filter method to filter strings by their length into a new vector named filtered_words.
We print the filtered vector to demonstrate the filtering.

Rust Program

fn main() {
    let words = vec!["apple", "banana", "cherry", "date", "fig"];
    let filtered_words: Vec<_> = words.into_iter().filter(|&word| word.len() > 5).collect();
    println!("Filtered Words: {:?}", filtered_words);
}

Output

Filtered Words: ["banana", "cherry"]

Summary

In this tutorial, we learned How to Filter Elements of an Array based on a Condition in Rust language with well detailed examples.

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How to Filter Elements of an Array based on a Condition in Rust - Step by Step Examples

How to Filter Elements of an Array based on a Condition in Rust ?

Answer

✐ Examples

1 Filter Even Numbers

Rust Program

Output

2 Filter Strings by Length

Rust Program

Output

Summary

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