How to Remove Items from Vector based on a Condition in Rust - Step by Step Examples

◀ Previous Next ▶

How to Remove Items from Vector based on a Condition in Rust ?

Answer

To remove items from a vector based on a condition in Rust, you can use the retain method or the filter method.

✐ Examples

1 Remove Items Using retain Method

In this example,

We start by creating a mutable vector named vec with some integer values.
We define a closure that specifies the condition for retaining elements. In this example, we want to keep elements less than 30.
We use the retain method to remove elements that do not satisfy the specified condition. The retain method takes a closure that returns true for elements to keep and false for elements to remove.
Finally, we print the modified vector to see the result.

Rust Program

fn main() {
    let mut vec = vec![10, 20, 30, 40, 50];
    vec.retain(|&x| x < 30);
    println!("Vector after removing items based on condition: {:?}", vec);
}

Output

Vector after removing items based on condition: [10, 20]

2 Remove Items Using filter Method

In this example,

We start by creating a vector named vec with some integer values.
We define a closure that specifies the condition for filtering elements. In this example, we want to keep elements less than 30.
We use the filter method to create an iterator over the vector that yields only elements satisfying the specified condition.
We collect the filtered elements into a new vector using the collect method.
Finally, we print the new vector to see the result.

Rust Program

fn main() {
    let vec = vec![10, 20, 30, 40, 50];
    let vec_new: Vec&lt;i32&gt; = vec.into_iter().filter(|&x| x < 30).collect();
    println!("Vector after removing items based on condition: {:?}", vec_new);
}

Output

Vector after removing items based on condition: [10, 20]

Summary

In this tutorial, we learned How to Remove Items from Vector based on a Condition in Rust language with well detailed examples.

◀ Previous Next ▶