How to check if a Set is Empty in C++ - Step by Step Examples
How to check if a Set is Empty in C++ ?
Answer
To check if a Set is empty in C++, you can use the empty method or compare the size to zero.
✐ Examples
1 Check if Set is Empty Using empty Method
In this example,
- We define a set named `mySet` containing elements of a specific type.
- We use the `empty` method to check if the set is empty.
- If the `empty` method returns `true`, then the set is empty; otherwise, it contains elements.
C++ Program
#include <iostream>
#include <set>
int main() {
// Define set
std::set<int> mySet;
// Check if set is empty using empty method
if (mySet.empty()) {
std::cout << "Set is empty" << std::endl;
} else {
std::cout << "Set is not empty" << std::endl;
}
return 0;
}
Output
Set is empty
2 Check if Set is Empty Using size Method
In this example,
- We define a set named `mySet` containing elements of a specific type.
- We use the `size` method to get the number of elements in the set.
- If the size is equal to zero, then the set is empty; otherwise, it contains elements.
C++ Program
#include <iostream>
#include <set>
int main() {
// Define set
std::set<int> mySet;
// Check if set is empty using size method
if (mySet.size() == 0) {
std::cout << "Set is empty" << std::endl;
} else {
std::cout << "Set is not empty" << std::endl;
}
return 0;
}
Output
Set is empty
Summary
In this tutorial, we learned How to check if a Set is Empty in C++ language with well detailed examples.
More C++ Sets Tutorials
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- How to create a Set of size N in C++ ?
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