How to find the Element with Minimum Number of Occurrences in a List in Kotlin - Step by Step Examples



How to find the Element with Minimum Number of Occurrences in a List in Kotlin ?

Answer

To find the element with the minimum number of occurrences in a list in Kotlin, you can use a map to count the occurrences.



✐ Examples

1 Find Least Frequent Integer in List

In this example,

  1. We create a list named data with several integer elements.
  2. We declare a mutable map to count the occurrences of each element.
  3. We iterate through the list to populate the map with counts.
  4. We find the element with the minimum count by iterating through the map.
  5. Finally, we print the least common element to standard output.

Kotlin Program

fun main() {
    val data = listOf(1, 2, 2, 3, 3, 3, 4)
    val count = mutableMapOf<Int, Int>()
    for (num in data) {
        count[num] = count.getOrDefault(num, 0) + 1
    }
    var leastCommon = data[0]
    var minCount = Int.MAX_VALUE
    for ((key, value) in count) {
        if (value < minCount) {
            minCount = value
            leastCommon = key
        }
    }
    println("Element with the minimum occurrences is: $leastCommon")
}

Output

Element with the minimum occurrences is: 1

2 Find Least Frequent String in List

In this example,

  1. We create a list named words with several string elements.
  2. We declare a mutable map to count the occurrences of each element.
  3. We iterate through the list to populate the map with counts.
  4. We find the element with the minimum count by iterating through the map.
  5. Finally, we print the least common element to standard output.

Kotlin Program

fun main() {
    val words = listOf("apple", "banana", "apple", "orange", "banana", "apple")
    val count = mutableMapOf<String, Int>()
    for (word in words) {
        count[word] = count.getOrDefault(word, 0) + 1
    }
    var leastCommon = words[0]
    var minCount = Int.MAX_VALUE
    for ((key, value) in count) {
        if (value < minCount) {
            minCount = value
            leastCommon = key
        }
    }
    println("Element with the minimum occurrences is: $leastCommon")
}

Output

Element with the minimum occurrences is: orange

Summary

In this tutorial, we learned How to find the Element with Minimum Number of Occurrences in a List in Kotlin language with well detailed examples.




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