How to Remove Element from List based on a Condition in Kotlin - Step by Step Examples
How to Remove Element from List based on a Condition in Kotlin ?
Answer
To remove elements from a list based on a condition in Kotlin, you can use the `removeIf` method.
✐ Examples
1 Remove Elements Greater Than a Threshold
In this example,
- We create a mutable list named
numbers
with some elements. - We specify the threshold value.
- We use the
removeIf
method of the list along with a lambda function to remove elements greater than the threshold. - Finally, we print the modified list to standard output.
Kotlin Program
fun main() {
val numbers = mutableListOf(1, 2, 3, 4, 5)
val threshold = 3
numbers.removeIf { it > threshold }
println("Modified list after removing elements greater than $threshold: $numbers")
}
Output
Modified list after removing elements greater than 3: [1, 2, 3]
2 Remove Elements Matching a Predicate
In this example,
- We create a mutable list named
names
with some elements. - We define a predicate function
isLongName
that returnstrue
if the length of the string is greater than a specified value. - We use the
removeIf
method of the list along with theisLongName
predicate to remove elements matching the predicate condition. - Finally, we print the modified list to standard output.
Kotlin Program
fun main() {
val names = mutableListOf("John", "Alice", "Michael", "Emma")
val maxLength = 5
val isLongName: (String) -> Boolean = { it.length > maxLength }
names.removeIf(isLongName)
println("Modified list after removing long names: $names")
}
Output
Modified list after removing long names: [John, Alice, Emma]
Summary
In this tutorial, we learned How to Remove Element from List based on a Condition in Kotlin language with well detailed examples.
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