How to get all the possible K length Substrings in a String in Swift - Step by Step Examples

How to get all the possible K length Substrings in a String in Swift ?

Answer

To get all possible K-length substrings in a string in Swift, you can use a combination of loops and the String method 'index'. This approach allows you to generate all substrings of a specified length from the given string.

✐ Examples

1 All possible 3-length substrings of "Hello World"

In this example,

First, we create a string named str with a value of "Hello World".
Next, we define a variable k with a value of 3, representing the length of the substrings we want to extract.
We initialize an empty array substrings of type [String] to store the resulting substrings.
We use a for loop to iterate through the string. The loop variable i starts from 0 and goes up to str.count - k to ensure we don't go out of bounds.
Within the loop, we calculate the start and end indices for each substring using str.index(str.startIndex, offsetBy: i) and str.index(str.startIndex, offsetBy: i + k) respectively.
We then use the calculated indices to extract the substring from str and append it to the substrings array.
Finally, we print each substring in the substrings array to the standard output.

Swift Program

let str = "Hello World"
let k = 3
var substrings = [String]()
for i in 0..<(str.count - k + 1) {
    let start = str.index(str.startIndex, offsetBy: i)
    let end = str.index(start, offsetBy: k)
    let substring = String(str[start..<end])
    substrings.append(substring)
}
for substring in substrings {
    print(substring)
}

Output

Hel
ell
llo
lo 
o W
 Wo
Wor
orl
rld

2 All possible 4-length substrings of "Swift Programming"

In this example,

First, we create a string named str with a value of "Swift Programming".
Next, we define a variable k with a value of 4, representing the length of the substrings we want to extract.
We initialize an empty array substrings of type [String] to store the resulting substrings.
We use a for loop to iterate through the string. The loop variable i starts from 0 and goes up to str.count - k to ensure we don't go out of bounds.
Within the loop, we calculate the start and end indices for each substring using str.index(str.startIndex, offsetBy: i) and str.index(str.startIndex, offsetBy: i + k) respectively.
We then use the calculated indices to extract the substring from str and append it to the substrings array.
Finally, we print each substring in the substrings array to the standard output.

Swift Program

let str = "Swift Programming"
let k = 4
var substrings = [String]()
for i in 0..<(str.count - k + 1) {
    let start = str.index(str.startIndex, offsetBy: i)
    let end = str.index(start, offsetBy: k)
    let substring = String(str[start..<end])
    substrings.append(substring)
}
for substring in substrings {
    print(substring)
}

Output

Swif
wift
ift 
ft P
t Pr
 Pro
Prog
rogr
ogra
gram
ramm
ammi
mmin
ming

Summary

In this tutorial, we learned How to get all the possible K length Substrings in a String in Swift language with well detailed examples.

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How to get all the possible K length Substrings in a String in Swift - Step by Step Examples

How to get all the possible K length Substrings in a String in Swift ?

Answer

✐ Examples

1 All possible 3-length substrings of "Hello World"

Swift Program

Output

2 All possible 4-length substrings of "Swift Programming"

Swift Program

Output

Summary

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