How to Sort a List in Ascending Order in Java - Step by Step Examples
How to Sort a List in Ascending Order in Java ?
Answer
To sort a list in ascending order in Java, you can use the Collections.sort()
method or the List.sort()
method.
✐ Examples
1 Sort a List of Integers in Ascending Order
In this example,
- We create a list named
numbers
and initialize it with integer values. - We call the
Collections.sort()
method with thenumbers
list to sort it in ascending order. - The
sort()
method sorts the elements in place, modifying the original list. - Finally, we print the sorted list to the console.
Java Program
import java.util.*;
public class Main {
public static void main(String[] args) {
List<Integer> numbers = new ArrayList<>(Arrays.asList(5, 2, 8, 1, 3));
Collections.sort(numbers);
System.out.println("Sorted list in ascending order: " + numbers);
}
}
Output
Sorted list in ascending order: [1, 2, 3, 5, 8]
2 Sort a List of Strings in Ascending Order
In this example,
- We create a list named
words
and initialize it with string values. - We call the
Collections.sort()
method with thewords
list to sort it in ascending order. - The
sort()
method sorts the elements in place, modifying the original list. - Finally, we print the sorted list to the console.
Java Program
import java.util.*;
public class Main {
public static void main(String[] args) {
List<String> words = new ArrayList<>(Arrays.asList("banana", "apple", "cherry"));
Collections.sort(words);
System.out.println("Sorted list in ascending order: " + words);
}
}
Output
Sorted list in ascending order: [apple, banana, cherry]
Summary
In this tutorial, we learned How to Sort a List in Ascending Order in Java language with well detailed examples.
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