How to Sort a Map by Values in Java - Step by Step Examples
How to Sort a Map by Values in Java ?
Answer
To sort a map by values in Java, you can convert the map entries to a list, sort the list by values, and then convert it back to a map. This method allows you to sort the map based on values.
✐ Examples
1 Sorting a Map by Values Using List Conversion
We can sort a map by values in Java by converting the map entries to a list, sorting the list by values, and then converting it back to a map.
For example,
- We start by importing the
java.util.HashMap
,java.util.LinkedHashMap
,java.util.List
,java.util.Map
, andjava.util.stream.Collectors
classes, which provide the necessary functions and data structures for working with maps and lists. - We declare and initialize a `HashMap` named
unsortedMap
with some key-value pairs. In this example, the map has string keys and integer values. - We convert the map entries to a list and sort the list by values using streams.
- We create a new `LinkedHashMap` from the sorted list of map entries to maintain the insertion order.
- We print the sorted map to the console using the `System.out.println` function to verify the sorting.
Java Program
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
public class Main {
public static void main(String[] args) {
// Declare and initialize an unsorted map
Map<String, Integer> unsortedMap = new HashMap<>();
unsortedMap.put("apple", 3);
unsortedMap.put("banana", 1);
unsortedMap.put("cherry", 2);
// Convert the map entries to a list and sort the list by values
List<Map.Entry<String, Integer>> sortedEntries = unsortedMap.entrySet()
.stream()
.sorted(Map.Entry.comparingByValue())
.collect(Collectors.toList());
// Create a new map from the sorted list of map entries
Map<String, Integer> sortedMap = new LinkedHashMap<>();
for (Map.Entry<String, Integer> entry : sortedEntries) {
sortedMap.put(entry.getKey(), entry.getValue());
}
// Print the sorted map
System.out.println("Sorted Map by Values: " + sortedMap);
}
}
Output
Sorted Map by Values: {banana=1, cherry=2, apple=3}
2 Sorting a Map by Values in Descending Order
We can sort a map by values in descending order in Java by converting the map entries to a list, sorting the list by values in descending order, and then converting it back to a map.
For example,
- We start by importing the
java.util.HashMap
,java.util.LinkedHashMap
,java.util.List
,java.util.Map
, andjava.util.stream.Collectors
classes, which provide the necessary functions and data structures for working with maps and lists. - We declare and initialize a `HashMap` named
unsortedMap
with some key-value pairs. In this example, the map has string keys and integer values. - We convert the map entries to a list and sort the list by values in descending order using streams.
- We create a new `LinkedHashMap` from the sorted list of map entries to maintain the insertion order.
- We print the sorted map to the console using the `System.out.println` function to verify the sorting.
Java Program
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
public class Main {
public static void main(String[] args) {
// Declare and initialize an unsorted map
Map<String, Integer> unsortedMap = new HashMap<>();
unsortedMap.put("apple", 3);
unsortedMap.put("banana", 1);
unsortedMap.put("cherry", 2);
// Convert the map entries to a list and sort the list by values in descending order
List<Map.Entry<String, Integer>> sortedEntries = unsortedMap.entrySet()
.stream()
.sorted(Map.Entry.<String, Integer>comparingByValue().reversed())
.collect(Collectors.toList());
// Create a new map from the sorted list of map entries
Map<String, Integer> sortedMap = new LinkedHashMap<>();
for (Map.Entry<String, Integer> entry : sortedEntries) {
sortedMap.put(entry.getKey(), entry.getValue());
}
// Print the sorted map
System.out.println("Sorted Map by Values (Descending): " + sortedMap);
}
}
Output
Sorted Map by Values (Descending): {apple=3, cherry=2, banana=1}
3 Sorting a Map with Numeric Keys by Values
We can sort a map with numeric keys by values in Java by converting the map entries to a list, sorting the list by values, and then converting it back to a map.
For example,
- We start by importing the
java.util.HashMap
,java.util.LinkedHashMap
,java.util.List
,java.util.Map
, andjava.util.stream.Collectors
classes, which provide the necessary functions and data structures for working with maps and lists. - We declare and initialize a `HashMap` named
unsortedMap
with some key-value pairs. In this example, the map has integer keys and string values. - We convert the map entries to a list and sort the list by values using streams.
- We create a new `LinkedHashMap` from the sorted list of map entries to maintain the insertion order.
- We print the sorted map to the console using the `System.out.println` function to verify the sorting.
Java Program
import java.util.HashMap;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
public class Main {
public static void main(String[] args) {
// Declare and initialize an unsorted map
Map<Integer, String> unsortedMap = new HashMap<>();
unsortedMap.put(3, "three");
unsortedMap.put(1, "one");
unsortedMap.put(2, "two");
// Convert the map entries to a list and sort the list by values
List<Map.Entry<Integer, String>> sortedEntries = unsortedMap.entrySet()
.stream()
.sorted(Map.Entry.comparingByValue())
.collect(Collectors.toList());
// Create a new map from the sorted list of map entries
Map<Integer, String> sortedMap = new LinkedHashMap<>();
for (Map.Entry<Integer, String> entry : sortedEntries) {
sortedMap.put(entry.getKey(), entry.getValue());
}
// Print the sorted map
System.out.println("Sorted Map by Values: " + sortedMap);
}
}
Output
Sorted Map by Values: {1=one, 2=two, 3=three}
Summary
In this tutorial, we learned How to Sort a Map by Values in Java language with well detailed examples.
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