How to Filter Elements of an Array based on a Condition in C++ - Step by Step Examples
How to Filter Elements of an Array based on a Condition in C++ ?
Answer
To filter elements of an array based on a condition in C++, you can use standard algorithms like std::copy_if or std::remove_if.
✐ Examples
1 Filter Even Numbers
In this example,
- We have an array named
numbers
containing integers. - We use std::copy_if algorithm with a lambda function to filter out even numbers into a new array named
evenNumbers
. - We print the filtered array to demonstrate the filtering.
C++ Program
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int main() {
vector<int> numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
vector<int> evenNumbers;
std::copy_if(numbers.begin(), numbers.end(), std::back_inserter(evenNumbers), [](int num){ return num % 2 == 0; });
cout << "Even Numbers: ";
for (int num : evenNumbers) {
cout << num << " ";
}
return 0;
}
Output
Even Numbers: 2 4 6 8 10
2 Filter Strings by Length
In this example,
- We have a vector named
words
containing strings. - We use std::copy_if algorithm with a lambda function to filter strings by their length into a new vector named
filteredWords
. - We print the filtered vector to demonstrate the filtering.
C++ Program
#include <iostream>
#include <algorithm>
#include <vector>
#include <string>
using namespace std;
int main() {
vector<string> words = {"apple", "banana", "cherry", "date", "fig"};
vector<string> filteredWords;
std::copy_if(words.begin(), words.end(), std::back_inserter(filteredWords), [](const string& word){ return word.length() > 5; });
cout << "Filtered Words: ";
for (const string& word : filteredWords) {
cout << word << " ";
}
return 0;
}
Output
Filtered Words: banana cherry
Summary
In this tutorial, we learned How to Filter Elements of an Array based on a Condition in C++ language with well detailed examples.
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