How to Remove Element from List based on a Condition in C++ - Step by Step Examples
How to Remove Element from List based on a Condition in C++ ?
Answer
To remove elements from a list in C++ using `std::list`, you can use the `remove_if` algorithm along with a lambda function.
✐ Examples
1 Remove Elements Greater Than a Threshold
In this example,
- We include the necessary headers for using
std::list
and algorithms. - We create a list named
numbers
with some elements. - We specify the threshold value.
- We use the
remove_if
algorithm along with a lambda function to remove elements greater than the threshold. - Finally, we print the modified list to standard output.
C++ Program
#include <iostream>
#include <list>
#include <algorithm>
int main() {
std::list<int> numbers = {1, 2, 3, 4, 5};
int threshold = 3;
numbers.remove_if([&threshold](int x) { return x > threshold; });
for (const auto& num : numbers) {
std::cout << num << " ";
}
return 0;
}
Output
1 2 3
2 Remove Elements Matching a Predicate
In this example,
- We include the necessary headers for using
std::list
and algorithms. - We create a list named
names
with some elements. - We define a predicate function
is_long_name
that returnstrue
if the length of the string is greater than a specified value. - We use the
remove_if
algorithm along with theis_long_name
predicate to remove elements matching the predicate condition. - Finally, we print the modified list to standard output.
C++ Program
#include <iostream>
#include <list>
#include <algorithm>
bool is_long_name(const std::string& name, int max_length) {
return name.length() > max_length;
}
int main() {
std::list<std::string> names = {"John", "Alice", "Michael", "Emma"};
int max_length = 5;
names.remove_if([&max_length](const std::string& name) { return is_long_name(name, max_length); });
for (const auto& name : names) {
std::cout << name << " ";
}
return 0;
}
Output
John Alice Emma
Summary
In this tutorial, we learned How to Remove Element from List based on a Condition in C++ language with well detailed examples.
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